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4x^2-5x+10=360
We move all terms to the left:
4x^2-5x+10-(360)=0
We add all the numbers together, and all the variables
4x^2-5x-350=0
a = 4; b = -5; c = -350;
Δ = b2-4ac
Δ = -52-4·4·(-350)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-75}{2*4}=\frac{-70}{8} =-8+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+75}{2*4}=\frac{80}{8} =10 $
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